3^(x+1)+18/3^x=29

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Solution for 3^(x+1)+18/3^x=29 equation: 



3^(x+1)+18/3^x=29

We move all terms to the left:

3^(x+1)+18/3^x-(29)=0



Domain of the equation: 3^x!=0

x!=0/1

x!=0

x∈R



We multiply all the terms by the denominator


(3^(x+1))*3^x-29*3^x+18=0

Wy multiply elements

(3^(x+1))*3^x-87x+18=0

We add all the numbers together, and all the variables

-87x+(3^(x+1))*3^x+18=0

We move all terms containing x to the left, all other terms to the right

-87x+(3^(x+1))*3^x=-18

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